Question

The maximum number of devotees among whom 540 oranges 450 apples and 630 bananas can be distributed in such a way that number of orange,apples and bananas remains the same

Answer 1

Answer:

90 devotees

Step-by-step explanation:

Find the prime factors of the three numbers:

540 = 2² x 3³ x 5

450 = 2 x 3² x 5²

630 = 2 x 3² x 5 x 7

Find the GCF:

CGF = 2 x 3² x 5 = 90

⇒The maximum number of devotees = 90

Number of fruits each devotee will get:

oranges = 540 ÷ 90 = 6

apples = 450 ÷ 90 = 5

Bananas = 630 ÷ 90 = 7

Answer: 90 devotees and each will get 6 oranges, 5 apples and 7 bananas.

Answer 2

Answer:

solution:

Each one would get 6 oranges,5 apples and 7 bananas

Step-by-step explanation:

solution:

It is given  that :

Number of oranges =540

Number of apples =450

Number of bananas=630

Factors of 540=2× 2× 5 ×3 ×3× 3

Factors of 450=2× 3× 5 ×3 × 5

Factors of 630=2 ×3 ×5 ×3× 7

Now, taking HCF

H.C.F= 2 ×3 ×3× 5

=90

∵ where HCF is highest common factor

Number of oranges distributed in each person= 540/90

=6

Number of apples distributed in each person=630/90

=7

Number of bananas distributed in each person=450/90

=5

So,Each one would get 6 oranges,5 apples and 7 bananas