The maximum number of digits in the repeating block of decimal expansion of
11/29
Please help
Answers
Answer: EXAMPLE TO SOLVE
5/7 = 0.714285714285…….. and 9/11 = 0.8181818………
Possible irrational numbers between them can be as follows:
0.72012001200012000001………
0.73013001300013000001…………
0.7501500150001500001………..
Note: Non-terminating non-recurring numbers are known as irrational numbers. Irrational numbers cannot be expressed in the form of p/q where q≠0. Numbers given above cannot be expressed in the form of p/q and hence are irrational.
Step-by-step explanation:
5/7 = 0.714285714285…….. and 9/11 = 0.8181818………
Possible irrational numbers between them can be as follows:
0.72012001200012000001………
0.73013001300013000001…………
0.7501500150001500001………..
Note: Non-terminating non-recurring numbers are known as irrational numbers. Irrational numbers cannot be expressed in the form of p/q where q≠0. Numbers given above cannot be expressed in the form of p/q and hence are irrational.
Answer:
When 1 is divided by 17, we get,
17
1
=0.
0588235294117647
So, the number of digit in the repeating block of digit in the decimal expansion of
17
1
=16
