Question

the maximum number of electron having n+l+m is equal to 0 in Zn²+ is​

Answer 1

Answer:

The electronic configuration 30Zn=1s2,2s22p6,3s23p63d10,4s2

l may be =1,2⇒p   &  d subshells

For, m=±l(non zero)

2p=4e−,3p=4e−  &  3d=8e−

Total =4+4+8=16 electrons.

Thus, the maximum number of electrons in the ground state of configuration of Zn which have l= any positive integral value and m= any non zero value is 16.

Hence, the answer is 1+6=7.

Explanation:

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