Question

The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum $m_s =- \frac{1}{2}$, is

Answer 1

For n=3,l=0,1,2 Ms should be - 1/2

l=0 is s-subshell where only 1 electron has Ms=-1/2

l=1 is p-subshell so 3 electrons with Ms=-1/2

l=2,d-subshell, so, 5 electrons with Ms=-1/2 Hence, total 9 electrons would have n=3 & Ms=-1/2