Question

the maximum number of molecules is present in.
1) 5L of N2 gas at stp.
2) 0.5g of H2 gas.
3) 10 g of O2 gas.
4) 15 L if H2 gas at stp

Answer 1

Answer:

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Answer 2

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Dear Student,

Dear Student,Please find below the solution to the asked query:

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles(ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles(ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles(iii) Number of moles in 0.5 g of H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles(ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles(iii) Number of moles in 0.5 g of H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles(iv) Number of moles in 10 g of O2 gas = (10 g / 32 g mol-1) = 0.312 moles

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles(ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles(iii) Number of moles in 0.5 g of H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles(iv) Number of moles in 10 g of O2 gas = (10 g / 32 g mol-1) = 0.312 molesHence, as we know that 1 mole of any gas has Avogadro number of molecules (6.022 x 1023) in it, we can say that the higher number of moles i.e. in 15 L of H2 gas will contain maximum number of molecules, as it has higher number of molar quantity.

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles(ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles(iii) Number of moles in 0.5 g of H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles(iv) Number of moles in 10 g of O2 gas = (10 g / 32 g mol-1) = 0.312 molesHence, as we know that 1 mole of any gas has Avogadro number of molecules (6.022 x 1023) in it, we can say that the higher number of moles i.e. in 15 L of H2 gas will contain maximum number of molecules, as it has higher number of molar quantity.Hope this information will clear your doubts about Some Basic Concepts of Chemistry.

Dear Student,Please find below the solution to the asked query:We can normalise all to one unit i.e. in terms of moles, from which we can say that whichever has greater molar quantity will contain greater number of molecules in it.(i) Number of moles in 15 L of H2 gas at STP. = (15 L / 22.4 L) = 0.67 moles(ii) Number of moles in 5 L of N2 gas at STP. = (5 L / 22.4 L) = 0.22 moles(iii) Number of moles in 0.5 g of H2 gas = (0.5 g / 2 g mol-1) = 0.25 moles(iv) Number of moles in 10 g of O2 gas = (10 g / 32 g mol-1) = 0.312 molesHence, as we know that 1 mole of any gas has Avogadro number of molecules (6.022 x 1023) in it, we can say that the higher number of moles i.e. in 15 L of H2 gas will contain maximum number of molecules, as it has higher number of molar quantity.Hope this information will clear your doubts about Some Basic Concepts of Chemistry.If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

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