The maximum number of optically active
stereoisomers that could exist for the
compound below
Br Be
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The maximum number of stereoisomers that a molecule can have is 2n , where n is the number of chiral centres. A molecule with three chiral centres will have 23=8 stereoisomers.
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Answer:
The maximum no. of optically active stereoisomers that could exist fo the compound below Br is 8
Explanation:
It is symmetrical
Chiral C = 4
For even no.of optical isomer = 2*n-1
= 2*4-1
= 2*3
=8
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