Question

The maximum number of points of intersection of five distinct lines and four distinct circles is

Answer 1

Answer:62

Step-by-step explanation:

Case(1):Point of intersection of 2 lines = 5C2 = 10

Case(2):Point of intersection of two circles = 2(4C2) =12

Case(3):Point of intersection of one line and one circle = 2(5C1)(4C1) = 40

So total point of intersection of 5 lines and 4 circles is sum of all cases = 10 + 12 + 40 = 62

MARK BRAINLIEST IF IT HELPED YOU...