Physics, asked by Krishnanunni1874, 11 months ago

The maximum number of possible interference
maxima for slit-separation equal to twice the
wavelength in Young’s double-slit experiment is
(a) three (b) five
(c) infinite (d) zero

Answers

Answered by Anonymous

0

Answer:

three

Thus, the maximum number of possible maxima observed are 2+1+2=5.

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