The maximum number of students among whom 429 mangoes and 715 oranges can be equally distributed is
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Maximum number of students among whom 429 mangoes and 715 oranges can be equally distributed is 143
Step-by-step explanation:
To find the maximum number of students among which the given number of mangoes and oranges should be equally distributed ,
We need to find the H.C.F of the given number of mangoes and oranges
⇒ H.C.F of (429,715)
429 = 3 × 11 × 13
715 = 5 × 11 × 13
Common factors are : 11 and 13
So, H.C.F = 11 × 13 = 143
Hence, maximum number of students among whom 429 mangoes and 715 oranges can be equally distributed is 143
Each of the 143 persons will get 3 mangoes and 5 oranges
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