Question

the maximum percentage error in the measurement of a rod having l =(20.00+0.01)​

Answer 1

The maximum percentage error is 0.05%

Explanation:

The given length of the rod = 20 + 0.01

Here $\Delta l=0.01$

The error in measurement of length

$=\frac{\Delta l}{l}$

Percentage error

$=\frac{\Delta l}{l}\times 100$

$=\frac{0.01}{20}\times 100$

$=0.05\%$

Hope this answer is helpful.

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Q: In a simple pendulum experiment, the maximum percentage error in the measurement of length is 2% and that in the observation of the time period is 3%. Then the maximum percentage error in determination of the acceleration due to gravity g is​ :

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