Question

The maximum percentage error in the measurement of
length of a rod I = (20.00 10.01) m is​

Answer 1

Given,

Least count of tape is 0.1cm

Least count of Vernier caliper is 0.01cm

Length, L=10cm

Width, W=1cm

area,A=Length×width=L×W

Take ln and differentiate,

A

ΔA

=

L

ΔL

+

W

ΔW

A

ΔA

=

10

0.1

+

1

0.01

=0.02=2percent

Hence, error in area is ±2 %