Question

the maximum range of a gun on horizontal terrain is 16km. If g=1/s2, what must be the muzzle velocity of the shell?​

Answer 1

Answer:

Horizontal Range R=  $\frac{u^{2}sin 2θ}{g}$

For maximum horizontal range θ=45°  

or, $R^{max}$ =  $\frac{u^{2} }{g}$​   ; where u is the muzzle velocity of the shell  

∴1600m=  $\frac{u^{2} }{10 m/s^{2} }$

 

∴u=400m/s