Question

The maximum range of a projectile is 100 km. Take g = 10 ms 2. The initial velocity of the
projectile will be:​

Answer 1

Answer:

1000m/s

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Answer 2

Answer:

10 √ 10 km / sec

Explanation:

Given :

Range = 100 km

Value of g = 10 m / sec²

We know if range is maximum :

Ф = 45 .

We have expression of Range :

R = u² sin 2 Ф / g

100 = u² sin 2 × 45 / 10

100 = u² sin 90 / 10

Value of sin 90 = 1

100 = u² / 10

u² = 1000

u = √ 1000

u = 10 √ 10 km / sec

Therefore , we get required velocity .