Question

The maximum range of projectile fired with some initial velocity is found to be hundred the maximum height reached by the projectile is

Answer 1

Answer:

Given:

Max range = 100 metres.

To find:

Maximum height by the projectile.

Calculation:

For max range, the projectile has to be thrown at an angle of 45° with the horizontal.

Max range = u²sin(2θ)/2g

Putting θ = 45° , max range = u²/g

Now,

max height = u²sin²(θ)/2g

Putting θ = 45°

Max height = u²sin²(45°)/2g

=> Max height = u²(½)/2g

=> Max height = u²/4g

=> Max height = ¼(max range)

=> Max Height = ¼(100)

=> Max height = 25 metres.

So the final answer is 25 metres