The maximum range of the gun along horizontal is 16000m. If g=10ms-1, the muzzle velocity of the shell will be
1) 400 2) 200 3) 800 4) 256
please say with solution don't send unnecessary answer
Answers
Answered by
0
Answer:
Horizontal Range R=
g
u
2
sin2θ
For maximum horizontal range θ=45
0
or, R
max
=
g
u
2
; where u is the muzzle velocity of the shell
∴1600m=
10m/s
2
u
2
∴u=400m/s
Hence,
option (B) is correct answer.
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