Physics, asked by roshan131m, 5 days ago

The maximum range of the gun along horizontal is 16000m. If g=10ms-1, the muzzle velocity of the shell will be
1) 400 2) 200 3) 800 4) 256
please say with solution don't send unnecessary answer ​

Answers

Answered by yerrarajani2010
0

Answer:

Horizontal Range R=

g

u

2

sin2θ

For maximum horizontal range θ=45

0

or, R

max

=

g

u

2

; where u is the muzzle velocity of the shell

∴1600m=

10m/s

2

u

2

∴u=400m/s

Hence,

option (B) is correct answer.

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