Question

The maximum range of the projectile down the incline plane is?

Answer 1

Inclined plane projectile :

Let θθ be the angle of projection with the horizontal and αα be angle of inclination with the horizontal.

Time taken

T=2usin(θ−α)gcosαT2usinθαgcosα

Range

R=2u2sin(θ−α)cosθgcos2αR2u2sinθαcosθgcos2α

Max Height attained

H=u2sin2(θ−α)gcosαHu2sin2θαgcosα

For Max range R,

2θ−α=π22θαπ2

So here, αα is 30°30 and θθ is 60°60,

Range will be 2u23g2u23g

^_^

please keep me has brainleist