Question

The maximum speed of particle performing
S.H.M. is 6.28 cm/s , if the length of its path is 8
cm,then its period is...​

Answer 1

Answer:

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Explanation:

v= 6.28

l of path = 8 cm

that means Amplitude A = 4 cm

v=omega*A

omega= v/A =6.28/4

time period= 2π/(omega)

= 6.28/(omega) =4 s