Question

The maximum spin multiplicity is for
A)V+2
B)Cr+2
C)Mn+2
D)Fe+2​

Answer 1

Answer:

C) Mn+2

Explanation:

Mn2+ is a d5 system... It has five unpaired electrons.... While V2+ has 3,Cr2+ has 4and Fe2+ has 4 unpaired electrons respectively... So spin multiplicity of Mn2+ is highest.... And the value of SM is (2s+1)=2*(5/2)+1=6

Answer 2

Option (C) is the correct answer

Mn+2 it is having d⁵ with 5 unpaired electrons.

Explanation:

• Spin multiplicity is referred to as the probable orientations of spin angular momentum
• Total spin quantum number (s) for the same spatial wave function.
• The possible orientation is measured 2s+1
• The maximum oxidation of spin multiplicity of 4d is 6.
• The lowest energy is the one with the greatest value of spin.

A)V⁺²  it is having d³ with 3 unpaired electrons.

B)Cr⁺²  it is having d⁴ with 4 unpaired electrons.

C)Mn⁺²  it is having d⁵ with 5 unpaired electrons.

D)Fe⁺² it is having d⁴ with 4 unpaired electrons.

• The ion with a maximum number of the unpaired electron will have a maximum spin multiplicity

Option (C)is the correct answer Mn⁺² it is having d⁵ with 5 unpaired electron.