Question

The maximum sum of the series S = 104 + 101 + 98 +... is​

Answer 1

Answer:

Answer is 95

Step-by-step explanation:

is it true and helping

Answer 2

The maximum sum of the series S = 104 + 101 + 98 +... is "1872".

Step-by-step explanation:

The given sum of the series S = 104 + 101 + 98

Here, a = 104, d = 101 - 104 = - 3

∴ $t_{n}$ = a + (n - 1)d = 0

⇒ 104 + (n - 1)(- 3) = 0

⇒ 104 - 3n + 3 = 0

∴ n = $\dfrac{107}{3}$ = 35.66≅ 36

∴ The maximum sum of the series S = $\dfrac{n}{2}$ ×(a + l)

= $\dfrac{36}{2}$ ×(104 + 0)

= 18 × 104

= 1872

Hence, the maximum sum of the series S = 104 + 101 + 98 +... is "1872".