The maximum tension in the lower link of a Porter governor is 580 N and the maximum stress in the
link is 30 N/mm2. If the link is of circular cross-section, determine its diameter
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Answer:
The diameter of cross section is 5mm.
Explanation:
Given data:
F = 580N
P = 30 N/mm² = 30MPa
P = 4F / πd
30 = 4×580 / πd
d = 4.96mm ≈ 5mm
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