Physics, asked by Priyanka7672, 1 year ago

The maximum tension inextensible ring radius 1m and mass density 0.1kg can bear 40 n the maximum angular velocity which rotated in circular path is

Answers

Answered by Sweetbuddy
5
HEY BUDDY HERE IS UR ANSWER ..


》Motion is not clearly explained , yet I assume the ring is required to rotate on axis passing through center of ring and is perpendicular to the ring’s cross section, just as vertical line in figure

r=1m

Circumference , C= 6.28m

Mass of the ring, M=6.28m*0.1m/kg

M= 0.628kg

Centrifugal force acting on ring circumference

Fc = M*r*(square of angular velocity)

Fc =40N ,given

Taking only numbers,

40=0.628*1*(square of angular velocity)

angular velocity (AV) = square root (40/0.628)

AV=7.98 radian/second

》Therefore maximum angular velocity at which the ring can be rotated safely is 7.98radian per second.

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