The maximum tension inextensible ring radius 1m and mass density 0.1kg can bear 40 n the maximum angular velocity which rotated in circular path is
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HEY BUDDY HERE IS UR ANSWER ..
》Motion is not clearly explained , yet I assume the ring is required to rotate on axis passing through center of ring and is perpendicular to the ring’s cross section, just as vertical line in figure
r=1m
Circumference , C= 6.28m
Mass of the ring, M=6.28m*0.1m/kg
M= 0.628kg
Centrifugal force acting on ring circumference
Fc = M*r*(square of angular velocity)
Fc =40N ,given
Taking only numbers,
40=0.628*1*(square of angular velocity)
angular velocity (AV) = square root (40/0.628)
AV=7.98 radian/second
》Therefore maximum angular velocity at which the ring can be rotated safely is 7.98radian per second.
Hope u like !!
》》 BE BRAINLY 《《
》Motion is not clearly explained , yet I assume the ring is required to rotate on axis passing through center of ring and is perpendicular to the ring’s cross section, just as vertical line in figure
r=1m
Circumference , C= 6.28m
Mass of the ring, M=6.28m*0.1m/kg
M= 0.628kg
Centrifugal force acting on ring circumference
Fc = M*r*(square of angular velocity)
Fc =40N ,given
Taking only numbers,
40=0.628*1*(square of angular velocity)
angular velocity (AV) = square root (40/0.628)
AV=7.98 radian/second
》Therefore maximum angular velocity at which the ring can be rotated safely is 7.98radian per second.
Hope u like !!
》》 BE BRAINLY 《《
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