Question

The maximum thrust extended by hydraulic ram is 40N the pressure of the liquid is 20N calculate the required diameter of r ram

Answer 1

Answer:

Explanation: Pressure= Force/ Area

20=40/πr^2

r^2= 2÷π

Answer 2

Answer:

The diameter of the hydraulic ram is 1.596m.

Explanation:

The relationship between force and pressure is given as,

$P=\frac{F}{A}$        (1)

Where,

P=pressure acting on the surface

F=force applied on the surface

A=area of the given surface=πr²

From the question we have,

F=40N

P=20 Nm⁻²

By substituting the required values in equation (1) we get;

$20=\frac{40}{\pi\times r^2}$

$r^2=\frac{40}{\pi\times 20}$

$r^2=0.6369$

$r=\sqrt{0.6369}$

$r=0.798 m$

Diameter of the ram=2r=$2\times 0.798=1.596m$

Hence, the diameter of the hydraulic ram is 1.596m.