Question

The maximum time period of a bucket full of water
whirled in a verticle circle of radius 10m so that the
water may not fall is (g = 10 ms )
(a) 2pi
(6) pi
(c) pi/2
(d) pi 2​

Answer 1

Answer: option (a) 2pi

Explanation:

The centripetal force by water on bucket should be greater than gravitational force on water, i.e.

mv^2/r = mg: m is mass of water, v is velocity of water, r is radius of bucket.

From above we get v as (rg)^1/2 i.e. 10ms^-1

Then the time period of revolution will be the circumference of bucket divided by the minimum velocity of water required i.e.

t = 2pi(r)/v

Thus the answer is 2 pi. There you go...

Answer 2

Answer:

Explanation: The centripetal force by water on bucket should be greater than gravitational force on water, i.e.

mv^2/r = mg: m is mass of water, v is velocity of water, r is radius of bucket.

From above we get v as (rg)^1/2 i.e. 10ms^-1

Then the time period of revolution will be the circumference of bucket divided by the minimum velocity of water required i.e.

t = 2pi(r)/v

Thus the answer is 2 pi.  hope this help full

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