The maximum time required to stop a car moving with a velocity 20 m/sec within a distance of 40m is
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as v^(2)-u^(2)=2as
-u^(2)=2as [v=0 as it comes to rest]
-u^(2)/2s=a
a=-(20)^(2)/2×40
a=5m/s^(2)
as t=v-u/a
t=0-20/-5
=4s
-u^(2)=2as [v=0 as it comes to rest]
-u^(2)/2s=a
a=-(20)^(2)/2×40
a=5m/s^(2)
as t=v-u/a
t=0-20/-5
=4s
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