Math, asked by peelasai18, 1 year ago

THE MAXIMUM VALUE OF 3sin²x+5cos²x is

Answers

Answered by kabirsingh18

3

Step-by-step explanation:

Hey there,

The maximum value of 3sin²x+5cos²x is,

when x = 0°

3sin²x+5cos²x = 3×0 + 5×1

3sin²x+5cos²x = 5

Hope it helps you

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