Question

the maximum value of 7/5-(x-2/3)² is​

Answer 1

The correct answer is $\frac{7}{5}$.

Given: The equation = $\frac{7}{5}-(x-\frac{2}{3} ) ^{2}$.

To Find: The maximum value of this equation.

Solution:

The square of any number is always positive. So $(x-\frac{2}{3} ) ^{2}$ will always be positive.

So if any positive number is subtracted from $\frac{7}{5}$ it will reduce its value.

So for maximum value of this equation $(x-\frac{2}{3} ) ^{2}$ = 0.

$\frac{7}{5}-(x-\frac{2}{3} ) ^{2}$

$\frac{7}{5}-0$ = $\frac{7}{5}$

Hence, the maximum value of this equation is $\frac{7}{5}$.

#SPJ2