The maximum value of 7 + 6x – 9x2 is
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The maximum value of y is 8.
We need to find the maximum value of the following expression :
y=7+6x-9x^2y=7+6x−9x
2
....(1)
For maximum value put \dfrac{dy}{dx}=0
dx
dy
=0
So,
\begin{gathered}\dfrac{d}{dx}(7+6x-9x^2)=0\\\\6-18x=0\\x=\dfrac{1}{3}\\\end{gathered}
dx
d
(7+6x−9x
2
)=0
6−18x=0
x=
3
1
Put x = 1/3 in equation (1) :
\begin{gathered}y=7+6\times \dfrac{1}{3}-9\times (\dfrac{1}{3})^2\\\\y=8\end{gathered}
y=7+6×
3
1
−9×(
3
1
)
2
y=8
So, the maximum value of y is 8.
Explanation:
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