the maximum value of index of refraction of a material
Attachments:
Answers
Answered by
3
is the answer option 4
maximum value of base angle for which light is totally reflected form hypotenuse.
(90∘−α)
= C = minimum value of angle of incidence at hypotenuse for total internal reflection
sin(90∘−α)=sinC=1μ
⇒cosα=1μ
⇒α=cos−1(1μ)
maximum value of base angle for which light is totally reflected form hypotenuse.
(90∘−α)
= C = minimum value of angle of incidence at hypotenuse for total internal reflection
sin(90∘−α)=sinC=1μ
⇒cosα=1μ
⇒α=cos−1(1μ)
prachi2805:
no 4th option is correct
wait
Answered by
3
2 +an a ksjjd dont know
Similar questions