Question

The maximum value of index of refraction
of a material of a prism which allows
the passage of light through it when
the refracting angle of prism is A is​

Answer 1

$\sqrt{1 + cot^{2}\frac{A}{2} }$ A=ie​ +ie =2ie

ie = A/2

new = 1/sinie

new = 1/A/2

new = $\frac{\sqrt{sin^{2}\frac{A}{2} + cos^{2}\frac{A}{2} } }{\sqrt{sin^{2} \frac{A}{2} } }$​

new = $\sqrt{1 + cot^2A/2}$