The maximum value of is
a) ½ b) √3
2
c) 1 d) 1
√2
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Step-by-step explanation:
If x∈R find the maximum value of
x4−3x2−6x+13−−−−−−−−−−−−−−−√−x4−x2+1−−−−−−−−−√
I tried this:
Let
y=x4−3x2−6x+13−−−−−−−−−−−−−−−√−x4−x2+1−−−−−−−−−√
For maxima dydx=0 and d2ydx2<0. However, the equation dydx=0 (after simplifying
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