Question

The maximum value of the function 4sin2x+3cos2x is

Answer 1

Answer:

Let f=4sin

2

x+3cos

2

x

⇒f=4sin

2

x+3(1−sin

2

x)

⇒f=4sin

2

x+3−3sin

2

x

⇒f=sin

2

x+3

We know that 3 is a constant and maximum value of sinx=1

Thus, the maximum value of the given expression can be

f

max

=3+(1) ^2

=3+1=4

Answer 2

Answer:

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