Question

The maximum value of the sum of the AP 50, 48, 46,44

Answer 1

Answer:

HOPE THIS BRING A SMILE IN YOUR FACE

Step-by-step explanation:

AP:50,48,46,44

a=50, d=48-50= -2

Sn=n/2×(2a+(n-1)d)

=n/2×(2(50)+(n-1)(-2)

=n/2×(100-2n+2)

=n/2×2(50-n+1)

=n(50-n+1)

=50n-n^2+n

Answer 2

Your answer is given below -::::

Given AP is 50,48,46,44,......

a=50,

d=−2

⇒Tn=a+(n−1)d=−2n+52

=>Tn=0

⇒n=26

∴ Maximum sum

S=2

26(50+0)

=650

Your answer is =>> 650