Question

the maximum value of y= –5x²+ 11x–20 is equal to a)11/10. b)–121/20. c)–301/40 d)–279/20​

Answer 1

Step-by-step explanation:

For maximum/ minimum value dydx=0⇒5(2x)−2(1)+0=0⇒x=15

Now at x=15,d2ydx2=10 which is positive so minima at x=15

Therefore ymin=5(15)2−2(15)+1=45

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