the maximum velocity at which a truck can safely travel without toppling over, on a curve of radius 250 m (the height of the centre of gravity of the truck above the ground is 1.5 m and the distance between the wheels is 1.5 m, the track being horizontal) is:
(a) 30
(b) 35
(c) 45
Answers
Answered by
7
Explanation:
Net moment about centre of gravity=>
m * 0.75 = m * ( v ² / r ) * 1.5
we get,
v = root ( ( r * g * 0.75 ) / 1.5 )
Putting all the values we get
v = 35.0 m/s
roshniranjan16:
FROM WHERE DID YOU GET 0.75? PLZ EXPLAIN ME......
(mv^2/r)* 1.5 = mg * 1.5/2
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