Question

The maximum velocity of a particle executing S.H.M. is 12.56 cm/s. Find the amplitude of oscillation if the period of oscillation is 8 sec.
Please help

Answer 1

For a SHM, x=Asin(ωt+ϕ)

Velocity, v=dtdx=Aωcos(ωt+ϕ)

So, vmax=Aω

or 4.4=7×10−3(2π/T)

or T=9.99×10−3=10×10−3=0.01s

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