The maximum velocity of a particle executing S.H.M.is
Vm. The average speed of the particle on completing
one oscillation will be
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Answer:
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Explanation:
Let the SHM be represented as x=Asin(ωt+ϕ)
Thus the speed of a particle= dx/dt =∣Aωcos(ωt+ϕ)∣
⇒V m =Aω
The average speed of the particle= ∫0^(2π/ω) ∣Aωcos(ωt+ϕ)∣ / 2π/ω
= 2Aω/π
= 2/π V m
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