Question

the maximum velocity of a particle executing S.H.M with amplitude of 7mm is 4.4m/s. what is the period of oscillation?​

Answer 1

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Answer 2

The period of oscillation is 0.01  seconds.

Explanation:

It is given that,

Amplitude of a particle in SHM, A = 7 mm = 0.007 m

Maximum velocity of the particle, v = 4.4 m/s

The maximum velocity of the particle in SHM is given by :

$v=\omega\times A$

$v=\dfrac{2\pi}{T}\times A$

$T=\dfrac{2\pi}{v}\times A$

$T=\dfrac{2\pi}{4.4}\times 0.007$

T = 0.01  seconds

So, the period of oscillation is 0.01  seconds. Hence, this is the required solution.

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Simple harmonic motion

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