Question

The maximum velocity of a particle performing of S.H.H is 6.28cm/sec. If the length of path is 8cm calculates it's period


A=8/2
=4cm

v(max)=6.28cm/sec

v(max)= A Omega
=A.2π/T

6.28=4×2π/T

2π=4×2π/T

T=4sec






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Answer 1

Answer:

t=4..as the answer is given above