The maximum wavelength of light that would excite an electron from energy level n= 1 to n=3 in atomic hydrogen is
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0
Answer:
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Explanation:
Answered by
6
Answer:
lemda = 102nm
Explanation:
Energy of 1st orbit = -13.6ev
Energy directly proportional to 1/n^2
Energy of 3rd orbit = -13.6ev/9 = -1.51ev
ΔE = 12.09ev
hc/lemda = 12.09ev
lemda= 102nm
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