Question

the mean and median of 100 item's are 50 and 52 respectively it was later found that the value of the largest item is recorded as 100 instead of 110 compute the corrected mean and median​

Answer 1

The mean and median of 100 items are 50 & 52

respectively. The value of the largest items

is 100. It was later found that it is 110.

The true mean and median are ________

Sol we know that Arithmetic mean =∑X/N

Given Mean =50

N=100

i.e, 50=

100

∑X

∑X=5000

Later found that it is 110

So the 100 items is wrong value

correct A.M = [∑X (wrong) + correct value of observation −

Incorrect value of observation]/N

correct Mean =[5000+110−100]/100

=[5110−100]/100

=

100

5010

=50.10

∴ The real or true mean value is 50.10

Median value is 52