Question

the mean and median of 100 observation are 50 and 52 respectively.the value of largest observation is 100.it was later found that it is 110 not 100. find the true mean and median​

Answer 1

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Arithmetic Mean = ∑X/N

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000Correct value = 110

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000Correct value = 110Incorrect value = 100

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000Correct value = 110Incorrect value = 100Correct Arithmetic Mean = {∑X (Wrong) + Correct value of observation - Incorrect value of observation }/N

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000Correct value = 110Incorrect value = 100Correct Arithmetic Mean = {∑X (Wrong) + Correct value of observation - Incorrect value of observation }/N⇒ Correct Mean = (5000 + 110 - 100)/100

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000Correct value = 110Incorrect value = 100Correct Arithmetic Mean = {∑X (Wrong) + Correct value of observation - Incorrect value of observation }/N⇒ Correct Mean = (5000 + 110 - 100)/100⇒ Correct mean = 5010/100

Arithmetic Mean = ∑X/NGiven : Mean = 50 and N = 100Therefore,50 = ∑X/100∑X (Wrong) = 5000Correct value = 110Incorrect value = 100Correct Arithmetic Mean = {∑X (Wrong) + Correct value of observation - Incorrect value of observation }/N⇒ Correct Mean = (5000 + 110 - 100)/100⇒ Correct mean = 5010/100⇒ Correct Mean = 50.1

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