Math, asked by MysteriousAryan, 4 days ago

The mean and standard deviation of a group of 100 observations were found to be 20 and 3 respectively. Later on it was found that three observations were incorrect which were recorded as 21,21 and 18. Find the mean and standard deviation if the incorrect observation are omitted

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Answers

Answered by OoxXIIGANGSTERIIXxoO
2

Simple distillation is a method for separating the solvent from a solution. For example, water can be separated from salt solution by simple distillation. This method works because water has a much lower boiling point than salt. When the solution is heated, the water evaporates.

Answered by ITZSnowyBoy
1

Answer:

Incorrect mean is 20 . There was 100 observations .

So sum of all observations = 20 × 100 = 2000

2000 - 21 - 21 - 18 = 1940

Correct Mean =

 \frac{1940}{100 - 3}  =  \frac{1940}{97}  = 20

Now , we will find the correct Standard Deviation

We know ,

σ =    \sqrt { \frac{1}{n}Σ(xi) {}^{2}  - (x) {}^{2}  }

When incorrect observations were present , the standard deviation was 9

3 =  \sqrt{ \frac{1}{100} Σ(xi) {}^{2} - (20) {}^{2}  }

9 =  \frac{1}{100} Σ(xi) {}^{2}  -400

40900 = Σ(xi) {}^{2}

This is the sum when observations were incorrect .

Correct sum when observations are omitted 40900 - 21 {}^{2}  - 21 {}^{2}  - 18 {}^{2}  = 39694

Correct Σ(xi) {}^{2}  = 39694

σ =  \sqrt{ \frac{1}{97} (39694) - 400}  =  \sqrt{409.16 - 400}  =  \sqrt{9.16}  = 3.03

So , the correct deviation is 3.03 .

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