the mean and standard deviation of a normal distribution are 60 and 9 respectively then the upper quartile is?
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Given : mean and standard deviation of a normal distribution are 60 and 9 respectively
To Find : the upper quartile
Solution:
Mean = 60
SD = 9
Z score = ( Value - Mean) / SD
Upper Quartile is 75 % of data => 0.75
From z score table value of
z score for 0.75 is 0.675
0.675 = ( Value - 60)/9
=> 6.075 = Value - 60
=> Value = 66.075
=> Value ≈ 66
Upper Quartile is 66
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