Question

the mean and the standard deviation of a data which is comprised of a set of 10 positive numbers are 8 and 2 respectively if the sum of squares of 9 among the ten number is 599 what is the 10th number​

Answer 1

Answer:

Navin additional data which is opposite of composite number and 2 respectively the sum of the squares of 9 and number is 5 million what is the check number bataiye

Answer 2

Given :- The mean and standard deviation of a data which is comprised of a set of ten positive numbers are 8 and 2 respectively .if the sum of squares of nine among the ten numbers is 599, what is the tenth number ?

Solution :-

Let us assume that, the 10th number is x .

we know that,

• standard deviation = √[{(sum of square of all numbers)/N} - (mean)²]

N = Number of terms.

Given that,

→ standard deviation = 2 .

→ Mean = 8 .

→ N = 10 .

→ sum of square of 9 numbers = 599.

→ 10th number = x .

So,

→ sum of square of all 10 numbers = sum of square of 9 numbers + (10th number)² = (599 + x²)

Putting all values now , we get :-

→ 2 = √[{(599 + x²)/10} - (8)²]

Squaring both sides , we get,

→ 4 = {(599 + x²)/10} - (8)²

→ 4 = {(599 + x²)/10} - 64

→ 4 + 64 = (599 + x²)/10

→ 68 * 10 = 599 + x²

→ x² = 680 - 599

→ x² = 81

Square root both sides we get,

→ x = 9 (Ans.)

Hence, the tenth number is 9.

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