the mean and variance of 12 items are 22 and 9 later on its was found that an item 32 was wrongly taken ans 23 compute correct mean and variance
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the mean and variance of 12 items are 22 and 9 later on its was found that an item 32 was wrongly taken as 23 then New Mean = 22.75 & New Variance = 16.7
Step-by-step explanation:
The mean and variance of 12 items are 22 and 9
Mean = 22
number of items = 12
Sum = 22 * 12 = 264
item 32 was wrongly taken as 23
=> New Total = 264 - 23 + 32
=> New Total = 273
New Mean = 273/12 = 22.75
Variance = ∑ xi² / n - (Mean)²
9 = ∑ xi² / 12 - 22²
=> ∑ xi² = 5916
New ∑ xi² = 5916 - 23² + 32² = 6411
New Mean = 22.75
New Variance = 6411/12 - (22.75)²
New Variance = 16.7
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