The mean and variance of two natural number are 3 and 4 respectively. Then Find those numbers
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Class 12
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>>Probability Distribution
>>Statement 1: The variance of first n eve
Question

Statement 1: The variance of first n even natural numbers is 4n2−1
Statement 2: The sum of first n natural numbers is 2n(n+1) and the sum of squares of first n natural numbers is 6n(n+1)(2n+1)
A
Statement 1 is true, Statement2 is true,Statement 2 is a correct explanation for Statement 1
B
Statement 1 is true, Statement2 is true;Statement2 is not a correct explanation for statement 1
Your Answer
C
Statement 1 is true, Statement 2 is false.
D
Statement 1 is false, Statement 2 is true
Correct Answer
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Solution

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Correct option is D)
Sum of first n even natural numbers
=2+4+6+...+2n=2(1+2+...+n)
=22n(n+1)=n(n+1)
Mean (xˉ)=nn(n+1)=n+1
variance =n1(∑x1)2−(xˉ)2=n1(22