Question

the mean and variances of a set of 10 values are know to be 17 and 33 respectively of the ten values one value 26 was subsequently found inaccurate and was weeded out​

Answer 1

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Answer 2

Thus the value of standard deviation is 5.16

Explanation:

• x = 17
• σ^2 = 33
• S.D = √33

33 = Σxi^2 / 10 - 289

Σxi^2 / 10 = 33

Σixi^2 = 3220

x (bar) =  Σixi / n = x1 + x2 + x3 ---- x10 / 10 = 17

Σixi  =  x1 + x2 + x3 ---- x10  = 170

x1 + x2 + x3 ---- + x9 = 144

Σixi   = 144

x (bar) = Σixi   / n = 144 / 9 = 16

S.D =  √ Σixi ^2 / n' - (x bar)^2

S.D =  √  2554 / 9 - (16)^2 / 1

S.D = √  250 / 9 = 5.16

Thus the value of standard deviation is 5.16