The mean deviation of weights about median for the following data:
Weight (lb): 131-140 141-150 151-160 161-170 171-180 181-190
No. of persons: 3
13
15
is given by
(a) 10.97
(b) 8.23
(c) 9.63
(d) 11.45
Answers
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Mean Deviation of Weights is 10.97
Explanation:
Please follow the Table-I from the file attached.
Where N = 50, So N/2 = 25
Since, 24 < 25 < 39, hence l = 160.5, Cumulative Frequency =24, f = 15 and C = 10
Since we know that, Me = l + { [N/2 - Cf]/f } x C
So, Me = 160.5 + (25 – 24) x10 / 15
Me = 160.5 + 0.66
Me = 161.66
Consider the II-table in the attached file.
Now, Mean Deviation about the Median = { I xi – Me I fi }/N
MD = 548.68 / 50 = 10
Attachments:
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