Question

the mean free path of a molecule of he gas is alpha .its mean free path along arbitrary coordinate axis will be

Answer 1

don't you know about mean free path ? because you understand the concept of mean free path , you can easily solve this type of questions.

well, mean free path of a gaseous molecule is average path length covered between two successive collision. and it is given by
$\bf{\lambda=\frac{k_BT}{\sqrt{2}\pi d^2p}}$
here $\lambda$ is mean free path.
d is diameter of particle .
T is temperature in kelvin.
P is pressure of gaseous molecule in container.
KB is. Boltzmann's constant.
here it is clear that mean free path doesn't depend upon direction of motion of particle.
hence, mean free path along arbitrary coordinate axis will be alpha.

Answer 2

Answer:Alpha/√3

Explanation:

Since mean free path is the vector suma of all three coordinate axes