Physics, asked by emmanuelzate1, 8 months ago

the mean free path of collision of gas molecules varies with its diameter(d) of the molecules as?​

Answers

Answered by Anonymous
3

Answer:

Explanation:

Mean free path of gas molecules

$ \, \, \, \, \, \, \, \, λ = \frac{λ_1 + λ_2 + ... + λ_n}{n}$

$ \, \, \, \, \, \, \, \, λ = \frac{1}{\sqrt{2} \pi nd^2}$

$ \, \, \, \, \, \, \, \, λ ∝ d^{-2}$

Answered by aaarathaur28peiyxw
0

what to prove write the full question I can't understand

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